Question

Phân tích thành phân tử x^3 + 1/27

Answer 1

\(x^3+\frac{1}{27}\)

\(=x^3+\left(\frac{1}{3}\right)^3\)

\(=\left(x+\frac{1}{3}\right)\left(x^2-\frac{1}{3}x+\left(\frac{1}{3}\right)^2\right)\)

\(=\left(x+\frac{1}{3}\right)\left(x^2-\frac{1}{3}x+\frac{1}{9}\right)\)

Trả lời hoài mà chẳng ai T bất công thiệt

Answer 2

\(x^3+\frac{1}{27}=\left(x+\frac{1}{3}\right)\left(x^2-\frac{1}{3}x+\frac{1}{9}\right)\)

(Nếu đúng thì clik cho mình với nhoa!)

Answer 3

\(x^3+\frac{1}{27}=x^3+\left(\frac{1}{3}\right)^3=\left(x+\frac{1}{3}\right)\left[x^2-x.\frac{1}{3}+\left(\frac{1}{3}\right)^2\right]=\left(x+\frac{1}{3}\right)\left(x^2+\frac{1}{3}x+\frac{1}{9}\right)\)

Answer 4

\(x^3+\frac{1}{27}\)

\(=x^3+\left(\frac{1}{3}\right)^3\)

\(=\left(x+\frac{1}{3}\right).\left(x^2-\frac{1}{3}.x+\frac{1}{9}\right)\)