Question

Phân tích thành nhân tử:

\((8-2x^2)^2 -18(x-2)(x+2)\)

Answer 1

\(=\left(2x^2-8\right)^2-18\left(x-2\right)\left(x+2\right)\\ =4\left(x^2-4\right)^2-18\left(x^2-4\right)\\ =\left(x^2-4\right)\left(4x^2-16-18\right)\\ =\left(x-2\right)\left(x+2\right)\left(4x^2-34\right)\\ =2\left(x^2-17\right)\left(x-2\right)\left(x+2\right)\)