Question

phân tích thành nhân tử

\(6x^4+5x^3-38x^2+5x+6\)

Answer 1

\(6x^4+5x^3-38x^2+5x+6\)

= \(6x^4-15x^3+6x^2+20x^3-50x^2+20x+6x^2-15x+6\)

= \(3x^2\left(2x^2-5x+2\right)+10x\left(2x^2-5x+2\right)+3\left(2x^2-5x+2\right)\)

= \(\left(2x^2-5x+2\right)\left(3x^2+10x+3\right)\)

= \(\left(2x^2-x-4x+2\right)\left[3x^2+x+9x+3\right]\)

= \(\left[x\left(2x-1\right)-2\left(2x-1\right)\right]\left[x\left(3x+1\right)+3\left(3x+1\right)\right]\)

= \(\left(x-2\right)\left(2x-1\right)\left(3x+1\right)\left(x+3\right)\)

Chúc bạn học tốt !!!