Question

Phân tích thành nhân tử:

\(12x^3+16x^2-5x-3\)

Answer 1

 = (12x^3-6x^2)+(22x^2-11x)+(6x-3)

 = (2x-1).(6x^2+11x+3)

 = (2x-1).[(6x^2+2x)+(9x+3)]

 = (2x-1).(3x+1).(2x+3)

k mk nha

Answer 2

 Ta có: \(12x^3+16x^2-5x-3\)

\(=12x^3-6x^2+22x^2-11x+6x-3\)

\(=6x^2\left(2x-1\right)+11x\left(2x-1\right)+3\left(2x-1\right)\)

\(=\left(2x-1\right)\left(6x^2+11x+3\right)\)

\(=\left(2x-1\right)\left(6x^2+9x+2x+3\right)\)

\(=\left(2x-1\right)\left(2x+3\right)\left(3x+1\right)\)