Question

Phân tích thành nhân tử :

X^2-3xy+xz-3yz

Answer 1

A=x^2-3xy+xz-3yz

A=x(x-3y)+z(x-3y)=(x-3y)(x+z) 

nghĩ thế :)

Answer 2

x ^ 2 - 3xy + xz - 3yz

= ( x ^ 2 + xz ) - ( 3xy + 3yz )

= x . ( x + z ) - 3y . ( x + z )

= ( x + z ) . ( x - 3y )

Answer 3

\(x^2-3xy+xz-3yz\)

\(=\left(x^2+xz\right)-\left(3xy+3yz\right)\)

\(=x.\left(x+z\right)-3y.\left(x+z\right)\)

\(=\left(x+z\right).\left(x-3y\right)\)