Question

Phân tích thành nhân tử : ( bằng nhiều cách ) x^2 - 5x + 6

Answer 1

cách 1 :  \(x^2\)\(-\)\(5x\)\(+\)\(6\)

\(=\)\(x^2\)\(-\)\(2x\)\(-\)\(3x\)\(+\)\(6\)

\(=\)\(\left(x^2-2x\right)-\left(3x-6\right)\)

\(=\)\(x\left(x-2\right)-3\left(x-2\right)\)

\(=\)\(\left(x-3\right)\left(x-2\right)\)

Cách 2 :  \(x^2\)\(-\)\(5x\)\(+\)\(6\)

\(=\)\(x^2\)\(-\)\(4x\)\(+\)\(4\)\(-\)\(x\)\(+\)\(2\)

\(=\)\(\left(x-2\right)^2\)\(-\)\(\left(x-2\right)\)

\(=\)\(\left(x-2\right)\)\(\left(x-2-1\right)\)

\(=\)\(\left(x-2\right)\left(x-3\right)\)

Answer 2

Mình chỉ biết một cách thôi

x^2-5x+6

=x^2-2x-3x+6

=x(x-2)-3(x-2)

=(x-3)(x-2)