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Question

Phân tích thành nhân tử :A= 6x - 9 - $x^2$B= $\left(3x+1\right)^2$- $\left(x+1\right)^2$

shitbo · Accepted Answer

$-A=x^2-6x+9=\left(x-3\right)^2\Rightarrow A=-\left(x-3\right)^2=\left(3-x\right)\left(x-3\right)$ $B=\left(3x+1\right)^2-\left(x+1\right)^2=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)$Câu trả lời: $-A=x^2-6x+9=\left(x-3\right)^2\Rightarrow A=-\left(x-3\right)^2=\left(3-x\right)\left(x-3\right)$ $B=\left(3x+1\right)^2-\left(x+1\right)^2=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)$

Nguyễn Văn Tuấn Anh · Answer

$A=6x-9-x^2$   $=-\left(x^2-6x+9\right)$  $=-\left(x-3\right)^2$ $B=\left(3x+1\right)^2-\left(x+1\right)^2$    $=\left(3x+1+x+1\right)\left(3x+1-x-1\right)$    $=\left(4x+2\right).2x$Câu trả lời: $A=6x-9-x^2$   $=-\left(x^2-6x+9\right)$  $=-\left(x-3\right)^2$ $B=\left(3x+1\right)^2-\left(x+1\right)^2$    $=\left(3x+1+x+1\right)\left(3x+1-x-1\right)$    $=\left(4x+2\right).2x$

ミ★๖ۣۜSεηαbĭ ๖ۣۜTĭʂт ๖ۣۜ... · Answer

$A=6x-9-x^2$$=-\left(x^2-6x+9\right)$$=-\left(x-3\right)^2$$B=\left(3x+1\right)^2-\left(x+1\right)^2$$=\left(3x+1+x+1\right)\left(3x+1-x-1\right)$$=\left(4x+2\right).2x$Câu trả lời: $A=6x-9-x^2$$=-\left(x^2-6x+9\right)$$=-\left(x-3\right)^2$$B=\left(3x+1\right)^2-\left(x+1\right)^2$$=\left(3x+1+x+1\right)\left(3x+1-x-1\right)$$=\left(4x+2\right).2x$

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