Question

Phân tích thành nhân tử  \(16y^2-x^2-2x-1\)

Answer 1

16y²-x²-2x-1

=16y²-(x²+2x+1)

=(4y)²-(x+1)²

=[4y-(x+1)][4y+(x+1)]

=(4y-x-1)(4y+x+1)

Answer 2

\(16y^2-x^2-2x-1=\left(4y\right)^2-\left(x^2+2x+1\right)=\left(4y\right)^2-\left(x+1\right)^2=\left(4y-x-1\right)\left(4y+x+1\right)\)