Question

Phân tích nhân tử bằng cách tách hạng tử
-10x² + 11x + 6
10x² - 4x - 6
-10x² + 4x +6
10x² + 7x - 6
Giúp mình với nha !!!! Cảm ơn trước ^^

Answer 1

       \(-10x^2+11x+6\)

\(=-10x^2-4x+15x+6\)

\(=-2x\left(5x+2\right)+3\left(5x+2\right)\)

\(=\left(-2x+3\right)\left(5x+2\right)\)

      \(10x^2-4x-6\)

\(=10x^2-10x+6x-6\)

\(=10x\left(x-1\right)+6\left(x-1\right)\)

\(=\left(10x+6\right)\left(x-1\right)\)

\(=2\left(5x+3\right)\left(x-1\right)\)

       \(-10x^2+4x+6\)

\(=-2\left(5x^2-2x-3\right)\)

\(=-2\left[5x^2-5x+3x-3\right]\)

\(=-2\left[5x\left(x-1\right)+3\left(x-1\right)\right]\)

\(=-2\left(x-1\right)\left(5x+3\right)\)

      \(10x^2+7x-6\)

\(=10x^2+12x-5x-6\)

\(=2x\left(5x+6\right)-\left(5x+6\right)\)

\(=\left(5x+6\right)\left(2x-1\right)\)