Question

phân tích đa thức thành nhân tử

\(x^5+5x^3+4x\)

Answer 1

Vũ Thanh Bình sai rùi

\(x^5+5x^3+4x\)

\(=x^5+4x^3+x^3+4x\)

\(=x^3.\left(x^2+4\right)+x\left(x^2+4\right)\)

\(=\left(x^3+x\right)\left(x^2+4\right)\)

\(=x\left(x^2+1\right)\left(x^2+4\right)\)

Answer 2

\(=x^5+4x^3+x^3+4x\)

\(=x^3\left(x^2+4\right)+x\left(x^2-4\right)\)

\(=\left(x^3+x\right)\left(x^2-2^2\right)\)

\(=x\left(x^2+1\right)\left(x-2\right)\left(x+2\right)\)

Answer 3

\(x^5+5x^3+4x\)

\(=x^5+x^3+4x^3+4x\)

\(=x^3\left(x^2+4\right)+x\left(x^2+4\right)\)

\(=\left(x^2+4\right)\left(x^3+x\right)\)

\(=x\left(x^2+1\right)\left(x^2+4\right)\)

Answer 4

= x(x²+1)(x²+4) 

nhẩm cũng ra, cx100%