Question

Phân tích đa thức thành nhân tử

x^3+4x^2+5x+2

 

Answer 1

    \(x^3+4x^2+5x+2\)

\(=x^3+2x^2+2x^2+4x+x+2\)

\(=x^2\left(x+2\right)+2x\left(x+2\right)+\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2+2x+1\right)\)

\(=\left(x+2\right)\left(x+1\right)^2\)

Answer 2

Có : x^3+4x^2+5x+2

= (x^3+x^2)+(3x^2+3x)+(2x+2)

= (x+1).(x^2+3x+2)

= (x+1).[(x^2+x)+(2x+2)]

= (x+1).(x+1).(x+2)

= (x+1)^2.(x+2)

Tk mk nha

Answer 3

(x+2)² (x+1)