Question

phân tích đa thức thành nhân tử

G= 2x²-3x+1

H= -x²+5x-4

I= x²+4x+3

K=2x²+7x+5

L=-3x²-5x-2

giúp mình với tý mình đi học rồi

thanks mng trước ạ

Answer 1

\(G=2x^2-3x+1=2x^2-2x-x+1\)

\(=2x\left(x-1\right)-\left(x-1\right)=\left(2x-1\right)\left(x-1\right)\)

\(H=-x^2+5x-4=-x^2+4x+x-4\)

\(=-x\left(x-4\right)+\left(x-4\right)=\left(1-x\right)\left(x-4\right)\)

\(I=x^2+4x+3=x^2+3x+x+3\)

\(=x\left(x+3\right)+\left(x+3\right)=\left(x+1\right)\left(x+3\right)\)

\(K=2x^2+7x+5=2x^2+2x+5x+5\)

\(=2x\left(x+1\right)+5\left(x+1\right)=\left(2x+5\right)\left(x+1\right)\)

\(L=-3x^2-5x-2=-3x^2-3x-2x-2\)

\(=-3x\left(x+1\right)-2\left(x+1\right)=\left(-3x-2\right)\left(x+1\right)\)