Question

phan tich da thuc thanh nhan tu

a,x⁴+2019x²+2018x+2019

b,(x+2)*(x+3)*(x+4)*(x+5)-24

Answer 1

\(x^4+2019x^2+2018x+2019\)

\(=x^4+x^2+1+2018\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+1\right)+2018\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+2019\right)\)

Answer 2

\(B=\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24\)

\(=\left(x^2+7x+10\right)\left(x^2+7x+12\right)-24\)

Đặt:  \(x^2+7x+10=t\)Khi đó B trở thành:

\(B=t\left(t+2\right)-24\)

\(=t^2+2t-24=\left(t-4\right)\left(t+6\right)\)

đến đây bạn thay trở lại