x(x-2)-y(2-x)-2(x-2)=3
x(x-2)+y(x-2)-2(x-2) =3
(x-2)(x+y-2)=3
\(x\left(x-2\right)-\left(2-x\right)y-2\left(x-2\right)=3\)
\(\Leftrightarrow x\left(x-2\right)+\left(x-2\right)y-2\left(x-2\right)=3\)
\(\Leftrightarrow\left(x-2\right)\left(x+y-2\right)=3\)
x ( x - 2 ) - ( 2 - x ) y - 2 ( x - 2 ) = 3
=> x ( x - 2 ) + ( x - 2 ) y - 2 ( x - 2 ) = 3
=> ( x - 2 ) ( x + y - 2 ) = 3