Question

phân tích đa thức thành nhân tử: x⁸+x⁶+x⁴+x²+1

Answer 1

= x^8 - x^7 + x^6 - x^5 + x^4 + x^7 - x^6 + x^5 - x^4 + x^3 + x^6 - x^5 + x^4 - x^3 + x^2 + x^5 - x^4 + x^3 - x^2 + x + x^4 - x^3 + x^2 - x + 1 
= (x^8 - x^7 + x^6 - x^5 + x^4) + (x^7 - x^6 + x^5 - x^4 + x^3) + (x^6 - x^5 + x^4 - x^3 + x^2) + (x^5 - x^4 + x^3 - x^2 + x) + (x^4 - x^3 + x^2 - x + 1) 
= x^4(x^4 - x^3 + x^2 - x + 1) + x^3(x^4 - x^3 + x^2 - x + 1) + x^2(x^4 - x^3 + x^2 - x + 1) + x(x^4 - x^3 + x^2 - x + 1) + (x^4 - x^3 + x^2 - x + 1) 
= (x^4 + x^3 + x^2 + x + 1)(x^4 - x^3 + x^2 - x + 1)

Answer 2

2222222222222222222222222222222222222222222222222222222222223333333

Answer 3

(x+2)/98+(x+4)/96=(x+6)/94+(x+8)/92 
<=>(x+2)/98+1+(x+4)/96+1=(x+6)/94+1+ (x+8)/92+1 
<=>(x+100)/98+(x+100)/96=(x+100)/94+ (x+100)/92 
<=>(x+100)(1/98+1/96-1/94-1/92)=0 
<=>x=-100(1/98+1/96-1/94-1/92 <> 0)