Question

phân tích đa thức thành nhân tử: x⁴+2008x² +2007x+2008

Answer 1

\(\left(x^4+x^2+1\right)+\left(2007x^2+2007x+2007\right)\)

=\(\left(x^2+x+1\right)\left(x^2-x+1\right)+2007\left(x^2+x+1\right)\)

=\(\left(x^2+x+1\right)\left(x^2-x+2008\right)\)

Answer 2

x^4_x+2008(x²+x+1)=x(x-1)(x2+x+1)+2008(x2+x+1)=(x2-x+2008)(x2+x+1)