Question

phân tích đa thức thành nhân tử :

x⁴ + 2007x² + 2006x + 2007

Answer 1

=x^4+2007x^2+2007x-x+2007 
=(x^4-x)+(2007x^2+2007x+2007) 
=x(x^3-1)+2007(x^2+x+1) 
=x(x-1)(x^2+x+1)+2007(x^2+x+1) 
=(x^2+x+1)(x(x-1)+2007) 
=(x^2+x+1)(x^2-x+2007)

Answer 2

 

x⁴ + 2007x² + 2006x + 2007

=x⁴-x³+2007x²+2017x+2017

=x.(x-1)(x²+x+1)+2007.(x²+x+1)

=(x²+x+1)(x²-x+2007)

Answer 3

x^4-x+2007*(x^2+x+1)=x*(x-1)*(x^2+x+1)+2007*(x^2+x+1)=(x^2+x+1)*(x^2-x+2007)