Question

Phân tích đa thức thành nhân tử x² -y²-4x-2y+3

Answer 1

x²-y²-4x-2y+3=(x²-4x+4)-(y²+2y+1)=(x-2)²-(y+1)²=(x-2+y+1)(x-2-y-1)

Answer 2

\(x^2-y^2-4x-2y+3\)

\(=\left(x^2-4x+4\right)-\left(y^2+2y+1\right)\)

\(=\left(x-2\right)^2-\left(y+1\right)^2\)

\(=\left(x-2-y-1\right)\left(x-2+y+1\right)\)

\(=\left(x-y-3\right)\left(x+y-1\right)\)