Question

phân tích đa thức thành nhân tử (x²-8)²+36

Answer 1

(x²-8)²+36=x⁴-16x²+100=x⁴+20x²+100-36x²=(x²+10)²-36x²=(x²+10-6x)(x²+10+6x)

Answer 2

chuan

Answer 3

Ta có: 

\(\left(x^2-8\right)^2+36\)

\(=x^4-16x^2+64+36\)

\(x^4=16x^2+100\)

$={}^{}-{}^{}$

$=\left({}^{}-6x+10\right)\left({}^{}-6x-10\right)$

=x4−16x2+64+36

Answer 4

Sorry, làm lại:

Ta có:

\(\left(x^2-8\right)^2+36\)

\(=x^4-16x^2+64+36\)

\(x=x^4-16x^2+100\)

\(=\left(x^4+20x^2+100\right)-36x^2\)

\(=\left(x^2+10\right)^2-\left(6x\right)^2\)

\(=\left(x^2-6x+10\right)\left(x^2-6x-10\right)\)