Question

phân tích đa thức thành nhân tử  (x-1)(x-2)(x+4)(x+5)-112

Answer 1

đánh nhầm chỗ "= 0" nhé!

Answer 2

\(\left(x-1\right)\left(x+4\right)\left(x-2\right)\left(x+5\right)-112\)

\(=\left(x^2+3x-4\right)\left(x^2+3x-10\right)-112\)

\(=\left(x^2+3x-7+3\right)\left(x^2+3x-7-3\right)-112\)

\(=\left(x^2+3x-7\right)^2-3^2-112\)

\(=\left(x^2+3x-7\right)^2-11^2\)

\(=\left(x^2+3x-7+11\right)\left(x^2+3x-7-11\right)\)

\(=\left(x^2+3x+4\right)\left(x^2+3x-18\right)=0\)

\(=\left(x^2+3x+4\right)\left(x+6\right)\left(x-3\right)\)