Question

Phân tích đa thức thành nhân tử (pp đặt nhân tử chung

 1/ \(x(y-z)+2(z-y)\)

2/\((2x-3y)(x-2)-(x+3)(3y-2x)\)

Mọi người giúp em với ạ. Em cảm ơn

 

Answer 1

x(y - z) + 2(z - y)

= x(y - z) - 2(y - z)

= (x - 2)(y - z)

(2x - 3y)(x - 2) - (x + 3)(3y - 2x)

= (2x - 3y)(x - 2) + (x + 2)(2x - 3y)

= (2x - 3y)(x - 2 + x + 2)

= 2x(2x - 3y)

Answer 2

1/\(x\left(y-z\right)+2\left(z-y\right)\)\(=\left(y-z\right)\left(x-2\right)\)

2/\(\left(2x-3y\right)\left(x-2\right)-\left(x+3\right)\left(3y-2x\right)\)\(=\left(2x-3y\right)\left(x-2+x+3\right)\)

\(=\left(2x-3y\right)\left(2x+1\right)\)

Answer 3

\(x\left(y-z\right)+2\left(z-y\right)\)

\(=x\left(y-z\right)-\left(y-z\right)\)

\(=\left(x-2\right)\left(y-z\right)\)