a) \(x^2-6x+8\)
\(=x^2-2\cdot x\cdot3+3^2-1\)
\(=\left(x-3\right)^2-1^2\)
\(=\left(x-3-1\right)\left(x-3+1\right)\)
\(=\left(x-4\right)\left(x-2\right)\)
Còn lại tương tự
a) \(x^2-6x+8=x^2-2x-4x+8\)
\(=\left(x^2-2x\right)-\left(4x-8\right)\)
=x(x-2)-4(x-2) = (x-2)(x-4)
mấy ý còn lại đợi xíu mk lm đã
\(x^2-6x+8=\left(x-4\right)\left(x-2\right)\)
\(9x^2+6x-8=\left(3x-2\right)\left(3x+4\right)\)
\(3x^2-8x+4=\left(x-2\right)\left(3x-2\right)\)
\(4x^2-4x-3=\left(2x-3\right)\left(2x+1\right)\)
\(x^2-7x+12=\left(x-3\right)\left(x-4\right)\)
\(x^2-5x-14=\left(x-7\right)\left(x+2\right)\)