Question

Phân tích đa thức thành nhân tử: 49 (x-4)^2 - 9(x+2)^2

Answer 1

`49(x-4)^2 - 9(x + 2)^2`

`= [7(x-4)]^2 - [3(x+2)]^2`

`= (7x - 28)^2 - (3x + 6)^2`

`= (7x - 28 - 3x - 6)(7x -28 + 3x + 6)`

`= (4x - 34)(10x -22)`

`= 4(5x-11)(2x-17)`

Answer 2

`49(x-4)^{2}-9(x+2)^{2`
`=[7(x-4)]^{2}-[3(x+2)]^{2}`
`=(7x-28)^{2}-(3x+6)^{2}`
`=(7x-28-3x-6)(7x-28+3x+6)`
`=(4x-34)(10x-22)`
`=4(5x-11)(2x-17)`