Question

Phân tích đa thức thành nhân tử 

36x^2-12x+1-y^2

a^2-2a+1-49b^2

4a^2+b^2+4ab-1

x^2+6xy+9y^2-36

100-x^2-2xy-y^2

4y^2-4x^2-4y+1

 

Answer 1

36x²-12x+1-y²=(36x²-12x+1)-y²=(6x-1)²-y²=(6x-1+y)(6x-1-y)

Answer 2

a²-2a+1-49b²=(a²-2a+1)-49b²=(a-1)²-(7b)²=(a-1-7b)(a-1+7b)

Answer 3

4a²+b²+4ab-1=(4a²+4ab+b²)-1=(2a+b)²-1=(2a+b-1)(2a+b+1)

Answer 4

x²+6xy+9y²-36=(x²+6xy+9y²)-36=(x+3y)²-6²=(x+3y-6)(x+3y+6)

Answer 5

100-x²-2xy-y²=(-x²-2xy-y²)+100=-(x²+2xy+y²)+100=(x+y)²-100=(x+y)²-10²=(x+y+10)(x+y-10)

Answer 6

36x²-12x+1-y²=(36x²-12x+1)-y²=(6x-1)²-y²=(6x-1+y)(6x-1-y)

a²-2a+1-49b²=(a²-2a+1)-49b²=(a-1)²-(7b)²=(a-1-7b)(a-1+7b)

4a²+b²+4ab-1=(4a²+4ab+b²)-1=(2a+b)²-1=(2a+b-1)(2a+b+1)

x²+6xy+9y²-36=(x²+6xy+9y²)-36=(x+3y)²-6²=(x+3y-6)(x+3y+6)

100-x²-2xy-y²=(-x²-2xy-y²)+100=-(x²+2xy+y²)+100=(x+y)²-100=(x+y)²-10²=(x+y+10)(x+y-10)