\(x^2+x-1\)=\(x^2+2x\frac{1}{2}+\frac{1}{4}-\frac{5}{4}\)=\(\left(x+\frac{1}{2}\right)^2-\left(\frac{\sqrt{5}}{2}\right)^2\)=\(\left(x+\frac{1}{2}-\frac{\sqrt{5}}{2}\right)\left(x+\frac{1}{2}+\frac{\sqrt{5}}{2}\right)\)
Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4
phan tich da thuc thanh nhan tu
x^5+x+1
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
phan tich da thuc sau thanh nhan tu: x5+x+1
phan tich da thuc thanh nhan tu x^5+x+1
x^8+x^4+1
phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu: x(x+2)(x^2+2x+2)+1
Phan tich da thuc thanh nhan tu (1+2x)(1-2x)-x(x+2)(x-2)
Phan tich da thuc thanh nhan tu x^2(1-x^2)-4-4x^2
