Question

Phân tích đa thức sau thành nhân tử:

A) \(16x-5x^2-3\)

B) \(x^3-3x^2+1-3x\)

C) \(x^3-3x^2-4x+12\)

D) \(\left(2x+1\right)^2-\left(x-1\right)^2\)

Mình đang cần lời giải (chi tiết). Cảm ơn

Answer 1

A/ \(16x-5x^2-3=\left(15x-3\right)-\left(5x^2-x\right)=3\left(5x-1\right)-x\left(5x-1\right)=\left(5x-1\right)\left(3-x\right)\)

B/ \(x^3-3x^2+1-3x=\left(x^3-4x^2+x\right)+\left(x^2-4x+1\right)=x\left(x^2-4x+1\right)+\left(x^2-4x+1\right)\)

\(=\left(x+1\right)\left(x^2-4x+1\right)\)

C/ \(x^3-3x^2-4x+12=x^2\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

D/ \(\left(2x+1\right)^2-\left(x-1\right)^2=\left(2x+1-x+1\right)\left(2x+1+x-1\right)=3x\left(x+2\right)\)

Answer 2

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