Question

Phân tích đa thức sau thành nhân tử:

4x(x-2y)+8y(2y-x)

 

Answer 1

Ta có:\(4x\left(x-2y\right)-8y\left(x-2y\right)\)

\(=\left(x-2y\right)\left(4x-8y\right)\)

\(=\left(x-2y\right)4\left(x-2y\right)\)

\(=\left(x-2y\right)^2.4\)

Answer 2

\(4x\left(x-2y\right)+8y\left(2y-x\right)\)

\(=4x\left(x-2y\right)-8\left(x-2y\right)\)

\(=\left(4x-8\right)\left(x-2y\right)\)

\(=4\left(x-2\right)\left(x-2y\right)\)

Answer 3

\(4x\left(x-2y\right)-8y\left(2y-x\right)\)

\(=4x\left(x-2y\right)+8y\left(x-2y\right)\)

\(=\left(x-2y\right)\left(4x+8y\right)\)

\(=\left(x-2y\right).4\left(x+2y\right)\)

Answer 4

\(4x\left(x-2y\right)+8y\left(2y-x\right)\)

\(=\left(x-2y\right)\left(4x-8y\right)\)

\(=\left(x-2y\right).4\left(x-2y\right)\)

\(=\left(x-2y\right)^2.4\)

Chắc vậy =))

Answer 5

\(4x\left(x-2y\right)+8y\left(2y-x\right)\)

\(=\left(x-2y\right)\left(4x-8y\right)\)

\(=\left(x-2y\right).4\left(x-2y\right)\)

\(=\left(x-2y\right)^2.4\)

Answer 6

\(4x\left(x-2y\right)+8y\left(2y-x\right)\)

\(=\left(x-2y\right)\left(4x-8y\right)\)

\(=\left(x-2y\right).4.\left(x-2y\right)\)

\(=\left(x-2y\right)^2.4\)