Question

Phân tich đa thức : 6x⁵ +15x⁴  + 20x³ +15x² + 6x +1 thành nhân tử

Answer 1

(2x+1)(x2+x+1)(3x2+3x+1)

Answer 2

6x^5+15x^4+20x^3+15x^2+6x+1

=3x^4(2x+1)+6x^3(2x+1)+7x^2(2x+1)+4x(2x+1)+(2x+1)

=(2x+1)(3x^4+6x^3+7x^2+4x+1)

=(2x+1)(3x^2(x^2+x+1)+3x(x^2+x+1)+(x^2+x+1)

=(2x+1)(x^2+x+1)(3x^2+3x+1)

Answer 3

6x⁵+15x⁴+20x³+15x²+6x+1

= (6x⁵+3x⁴)+(12x⁴+6x³)+(14x³+7x²)+(8x²+4x)+(2x+1)

= (2x+1)(3x⁴+6x³+7x²+4x+1)

= (2x+1)[(3x⁴+3x³+3x²)+(3x³+3x²+3x)+(x²+x+1)]

= (2x+1)(x²+x+1)(3x²+3x+1)

Answer 4

ko bít