14 + 6\(\sqrt{5}\)=9+ 2.3.\(\sqrt{5}\)+5
=(3 + \(\sqrt{5}\))2
12 - \(\sqrt{140}\)= 7- 2\(\sqrt{35}\)+5
=(\(\sqrt{7}\)-\(\sqrt{5}\))2
14 + 6\(\sqrt{5}\)=9+ 2.3.\(\sqrt{5}\)+5
=(3 + \(\sqrt{5}\))2
12 - \(\sqrt{140}\)= 7- 2\(\sqrt{35}\)+5
=(\(\sqrt{7}\)-\(\sqrt{5}\))2
Phân tích các biểu thức sau thành các lũy thừa bậc hai:
a) \(8+2\sqrt{15}\) b) \(10-2\sqrt{21}\) c) \(12-\sqrt{140}\) d) \(5+\sqrt{24}\) e) \(14+6\sqrt{5}\) g) \(8-\sqrt{28}\)
Tính:
1) \(\sqrt{14-2\sqrt{33}}\)
2) \(\sqrt{12-2\sqrt{35}}\)
3) \(\sqrt{16-2\sqrt{55}}\)
4) \(\sqrt{14-6\sqrt{5}}\)
5) \(\sqrt{17-12\sqrt{2}}\)
6) \(\sqrt{27-12\sqrt{5}}\)
7) \(\sqrt{4+\sqrt{15}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
giúp em với ạ
\(\sqrt{5
+2\sqrt{ }6}\)
\(\sqrt{12+2\sqrt{ }35}-\sqrt{12-2\sqrt{ }35}\)
\(\sqrt{16+6\sqrt{ }7}\)
\(\sqrt{31-12\sqrt{ }3}\)
\(\sqrt{27+10\sqrt{ }2}\)
\(\sqrt{14+6\sqrt{ }5}\)
Phân tích :
1) \(\sqrt{29+12\sqrt{5}}\) - \(\sqrt{29-12\sqrt{5}}\)
2) \(\sqrt{8-2\sqrt{15}}\)- \(\sqrt{23-4\sqrt{15}}\)
3) \(\sqrt{8-2\sqrt{15}}\) + \(\sqrt{48+6\sqrt{15}}\)
4) \(\sqrt{49-5\sqrt{96}}\)+\(\sqrt{49+5\sqrt{96}}\)
5) \(\sqrt{15-6\sqrt{15}}\)+\(\sqrt{33-12\sqrt{6}}\)
6) \(\sqrt{16-6\sqrt{7}}\)+\(\sqrt{64-24\sqrt{7}}\)
7) \(\sqrt{14-6\sqrt{5}}\)+\(\sqrt{14+6\sqrt{5}}\)
8) \(\sqrt{1-6\sqrt{2}}\)+\(\sqrt{11-6\sqrt{2}}\)
9) \(\sqrt{13+4\sqrt{10}}\)+\(\sqrt{13-4\sqrt{10}}\)
10) \(\sqrt{46-6\sqrt{5}}\)+\(\sqrt{29-12\sqrt{5}}\)
\(6-12\sqrt{15}+3\sqrt{5}-30\sqrt{3}\) phân tích thành nhân tử hộ e ạ
\(\dfrac{\sqrt{10}-\sqrt{15}}{\sqrt{8}-\sqrt{12}}\)
\(\dfrac{\sqrt{6}-\sqrt{15}}{\sqrt{35}-\sqrt{14}}\)
\(\dfrac{5+\sqrt{5}}{\sqrt{10}+\sqrt{2}}\)
rút gọn
a,\(\dfrac{\sqrt{10}-\sqrt{15}}{\sqrt{8}-\sqrt{12}}\) b,\(\dfrac{\sqrt{15}-\sqrt{6}}{\sqrt{35}-\sqrt{14}}\) c,\(\dfrac{5+\sqrt{5}}{\sqrt{10}+\sqrt{2}}\)
B 5. Rút gọn các biểu thức sau:
a)\(\sqrt{7+4\sqrt{3}}\) b)\(\sqrt{9-4\sqrt{5}}\)
c)\(\sqrt{14+6\sqrt{5}}\) d)\(\sqrt{17-12\sqrt{2}}\)
a : \(\sqrt{\left(2\sqrt{2}-1\right)^2}-\sqrt{17+12\sqrt{2}}\)
b : \(\sqrt{\left(2-\sqrt{5}\right)^2}+\sqrt{14-6\sqrt{5}}\)
c : \(\sqrt{\left(4-3\sqrt{2}\right)^2}-\sqrt{19+6\sqrt{2}}\)