\(P=\frac{2\left(\sqrt{8}-\sqrt{3}\right)}{\sqrt{6}\left(\sqrt{3}-\sqrt{8}\right)}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{6}\left(\sqrt{5}+\sqrt{27}\right)}\)
\(=-\frac{2}{\sqrt{6}}-\frac{1}{\sqrt{6}}=\frac{-3}{\sqrt{6}}=-\frac{\sqrt{6}}{2}\)
Trả lời:
\(P=\frac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
\(P=\frac{2\sqrt{8}-2\sqrt{3}}{\sqrt{18}-\sqrt{48}}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
\(P=\frac{2.\left(\sqrt{8}-\sqrt{3}\right)}{\sqrt{6}.\left(\sqrt{3}-\sqrt{8}\right)}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{6}.\left(\sqrt{5}+\sqrt{27}\right)}\)
\(P=\frac{-2.\left(\sqrt{3}-\sqrt{8}\right)}{\sqrt{6}.\left(\sqrt{3}-\sqrt{8}\right)}-\frac{1}{\sqrt{6}}\)
\(P=\frac{-2}{\sqrt{6}}-\frac{1}{\sqrt{6}}\)
\(P=\frac{-3}{\sqrt{6}}\)
\(P=\frac{-\sqrt{6}}{2}\)
Học tốt
