Question

P=(\(\dfrac{4x}{2+x}\) + \(\dfrac{8x^2}{4-x^{ }2}\)) : (\(\dfrac{x-1}{x^2-2x}\) - \(\dfrac{2}{x}\)) (x≠0; x≠2; x≠1)

Answer 1

help meee ɜː

Answer 2

\(P=\left(\dfrac{4x\left(2-x\right)}{\left(2+x\right)\left(2-x\right)}+\dfrac{8x^2}{\left(2+x\right)\left(2-x\right)}\right):\left(\dfrac{x-1}{x\left(x-2\right)}-\dfrac{2\left(x-2\right)}{x\left(x-2\right)}\right)\)

\(=\left(\dfrac{4x\left(x+2\right)}{\left(x+2\right)\left(2-x\right)}\right):\left(\dfrac{3-x}{x\left(x-2\right)}\right)=\dfrac{4x}{\left(2-x\right)}.\dfrac{x\left(2-x\right)}{x-3}\)

\(=\dfrac{4x^2}{x-3}\)

Answer 3