\(P=3^0+3^1+3^2+...+3^{99}\)
\(3P=3^1+3^2+3^3+...+3^{100}\)
\(3P-P=\left(3^1+3^2+3^3+...+3^{100}\right)-\left(3^0+3^1+3^2+...+3^{99}\right)\)
\(2P=3^{100}-3^0\)
\(P=\frac{3^{100}-3^0}{2}\)
=))
Ban lazy girl lam dung roi sao phai giup nua.Dung roi ma!!!