Question

P= 2⁰+2¹+2²+...+2²⁰¹⁰; Q= 2²⁰¹¹ so sánh P và Q

Answer 1

bạn tính P=2^2011-2

suy ra : P<Q

Answer 2

2P = 2 + 2^2 + ... + 2^2011

2P - P = (2 - 2) + (2^2 - 2^2) + ......  + (2^2010 - 2^2010) + 2^2011 - 1

P = 2^2011 - 1

2^2011 > 2^2011 - 1

Vậy P < Q 

Tích há 

Answer 3

\(P=2^0+2^1+2^2+...+2^{2010}\)

\(2P=2^1+2^2+2^3+...+2^{2011}\)

\(2P-P=\left(2^1+2^2+2^3+...+2^{2011}\right)-\left(2^0+2^1+2^2+...+2^{2010}\right)\)

\(P=2^{2011}-2^0\)

\(P=2^{2011}-1\)

Vì \(2^{2011}-1<2^{2011}\)

Nên P<Q

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