a.b.
Bảo toàn C: \(n_C=n_{CO_2}=\dfrac{8,96}{22,4}=0,4mol\)
Bảo toàn H: \(n_H=2.n_H=2.\dfrac{10,8}{18}=1,2mol\)
\(n_O=\dfrac{9,2-\left(0,4.12+1,2.1\right)}{16}=0,2mol\)
\(\Rightarrow CTPT:C_xH_yO_z\)
\(x:y:z=0,4:1,2:0,2=2:6:1\)
\(\Rightarrow CTPT:C_2H_6O\)
\(CTCT:CH_3-CH_2-OH\)
\(CH_3-O-CH_3\)
c.\(n_{CO_2}=\dfrac{8,96}{22,4}=0,4mol\)
\(n_{Ba\left(OH\right)_2}=\dfrac{300.14,25\%}{171}=0,25mol\)
\(Ba\left(OH\right)_2+CO_2\rightarrow BaCO_3+H_2O\)
0,25 < 0,4 ( mol )
0,25 0,25 ( mol )
\(m_{BaCO_3}=0,25.197=49,25g\)