Bs: \(x,y\in \mathbb{Z}\)
\(\Rightarrow x\left(2y+1\right)+\left(2y+1\right)=5\\ \Rightarrow\left(2y+1\right)\left(x+1\right)=5=5.1=\left(-5\right)\left(-1\right)\)
\(x+1\) | 5 | 1 | -5 | -1 |
\(2y+1\) | 1 | 5 | -1 | -5 |
\(x\) | 4 | 0 | -6 | -2 |
\(y\) | 0 | 2 | -1 | -3 |
\(\Rightarrow\left(x;y\right)\in\left\{\left(4;0\right);\left(0;2\right);\left(-6;-1\right);\left(-2;-3\right)\right\}\)