Câu 1:
a) \(V_{Cl_2}=0,4.22,4=8,96\left(l\right)\)
b) \(n_{H_2}=\dfrac{1,2.10^{23}}{6.10^{23}}=0,2\left(mol\right)=>V_{H_2}=0,2.22,4=4,48\left(l\right)\)
c) \(n_{CH_4}=\dfrac{4}{16}=0,25\left(mol\right)=>V_{CH_4}=0,25.22,4=5,6\left(l\right)\)
Câu 2
a) \(m_{Cu}=0,3.64=19,2\left(g\right)\)
b) \(m_{NaOH}=0,1.40=4\left(g\right)\)
c) \(n_{Zn}=\dfrac{1,5.10^{23}}{6.10^{23}}=0,25\left(mol\right)=>m_{Zn}=0,25.65=16,25\left(g\right)\)
d) \(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)=>n_{KOH}=0,1\left(mol\right)=>m_{KOH}=0,1.56=5,6\left(g\right)\)
Câu 3
a) \(n_{CuSO_4}=\dfrac{24}{160}=0,15\left(mol\right)\)
b) \(n_{NH_3}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
c) \(n_{Al}=\dfrac{1,8.10^{23}}{6.10^{23}}=0,3\left(mol\right)\)
Câu 1:
\(a,V_{Cl_2}=0,4.22,4=8,96(l)\\ b,n_{H_2}=\dfrac{1,2.10^{23}}{6.10^{23}}=0,2(mol)\\ \Rightarrow V_{H_2}=0,2.22,4=4,48(l)\\ c,n_{CH_4}=\dfrac{4}{16}=0,25(mol)\\ \Rightarrow V_{CH_4}=0,25.22,4=5,6(l)\)
