Ta có: \(\hept{\begin{cases}\frac{x}{2}=\frac{y}{6}\\x-y=2\end{cases}\Rightarrow\frac{x}{2}=\frac{y}{6}=\frac{x-y}{2-6}=\frac{2}{-4}=\frac{-1}{2}.}\)
\(\Rightarrow\hept{\begin{cases}x=\frac{-1}{2}.2=-1\\y=\frac{-1}{2}.6=-3\end{cases}}\)
Vậy x = -1 và y = -3
Ủng hộ tớ nha
Tim x;y;z biet x*y*z=A va neu x+1 thi A+1; neu y+2 thi A+2; neu z+2 thi A+8
Cho x va y là 2 dai luong ti le nghich neu x=2,4 thi y=25 \
a)tim he so ti le
b)viet cong thuc
c)tinh y khi x=6;-4;-1,2;-0,2
d)tinh x khi y=2;12;-2,5
cho hàm số y=f(x)= 1/2 * x - 3 neu x lon hon hoac bang 6 va bang 3-1/2 * x neu x<6 ham so tren co the viet gon boi cong yhuc nao khong
Gia su x = a/m;y = b/m (a;b;m thuoc Z;m>0) va x< y. Hay chung to rang neu chon z = a+b/2m thi ta co x<y<z
gia su x=a/m. y=b/m (a,b,m la so nguyen, m>0) va x<y. hay chung to rang neu chon z=a+b/2m thi ta co x<z<y
neu x/2y=5/6 thi x/y=
c1: Tap hop cac gia tri nguyen cua x thoa man \(\left(x+\frac{5}{4}\right)\left(x-\frac{19}{7}\right)\)<0
c2: Neu x,y la cac so nguyen thoa man 2xy+4y=6 thi y co the nhan nhung gia tri nam trong tap hop nao
c3: tim 3 so x,y,z biet x+y=8,x+z=10,y+z=12
C4: Gia tri cua x thoa man (x+3)^2=25 va x^3>0 la x=
Tim x,y va z neu \(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
gia su x=a/m,y=b/m (a,b,m thuoc Z,m>0) va x>y.Hay chung to rang neu chon z=a+b/2m thi ta co x<z<y
