a) Có: \(n_{HCl}=0,5mol\)
\(\Rightarrow m_{HCl}=0,5.\left(1+35,5\right)=18,25g\)
b)
\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\)
Có: \(n_{HCl}=0,5mol\)
Theo PTHH:
\(\Rightarrow n_{H_2}=0,25mol\)
\(\Rightarrow V_{H_2}=0,25.22,4=5,6l\)
\(n_{Zn}=0,25mol\)
\(\Rightarrow m_{Zn}=0,25.65=16,25g\)