Tổng số nu : \(N=\dfrac{0,306.2}{3,4.10^{-4}}=1800\left(nu\right)\)
Có : \(\left\{{}\begin{matrix}T=\dfrac{3}{2}G\\T+G=\dfrac{N}{2}=900\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}A=T=540\left(nu\right)\\G=C=360\left(nu\right)\end{matrix}\right.\)
-> Chọn A