\(m_C=\dfrac{88.54,5}{100}=48\left(g\right)=>n_C=\dfrac{48}{12}=4\left(mol\right)\)
\(m_H=\dfrac{88.9,1}{100}=8\left(g\right)=>n_H=\dfrac{8}{1}=8\left(mol\right)\)
\(m_O=\dfrac{36,4.88}{100}=32\left(g\right)=>n_O=\dfrac{32}{16}=2\left(mol\right)\)
=> CTHH: C4H8O2