Ta có:\(\frac{x+21}{1998}-\frac{x+25}{1994}+\frac{x+63}{652}-\frac{x+75}{648}=0\)
\(\Rightarrow\frac{x+21}{1998}-\frac{x+25}{1994}+\frac{x+63}{652}-\frac{x+75}{648}+4-4=0\)
\(\Rightarrow\frac{x+21}{1998}+1-\frac{x+25}{1994}-1+\frac{x+63}{652}+3-\frac{x+75}{648}-3=0\)
\(\Rightarrow\frac{x+2019}{1998}-\frac{x+2019}{1994}-\frac{x+2019}{652}+\frac{x+2019}{648}=0\)
\(\Rightarrow\left(x+2019\right)\times\left(\frac{1}{1998}-\frac{1}{1994}+\frac{1}{652}-\frac{1}{648}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+2019=0\\\frac{1}{1998}-\frac{1}{1994}+\frac{1}{652}-\frac{1}{648}=0\end{cases}}\)
Vì \(\frac{1}{1998}-\frac{1}{1994}+\frac{1}{652}-\frac{1}{648}\ne0\)
\(\Rightarrow x+2019=0\)
\(\Rightarrow x=-2019\)
Vậy \(x=-2019\)
