\(\left(4n-5\right)⋮\left(2n-1\right)\)
Ta có \(\left(2n-1\right)⋮\left(2n-1\right)\)
Nên \(2\left(2n-1\right)⋮\left(2n-1\right)\)
Mà \(\left(4n-5\right)⋮\left(2n-1\right)\)
=> \(\left(4n-5\right)-2\left(2n-1\right)⋮\left(2n-1\right)\)
=> \(\left(4n-5\right)-\left(4n-2\right)⋮\left(2n-1\right)\)
=> \(3⋮\left(2n-1\right)\)
=> \(2n-1\varepsilonƯ\left(3\right)=\left\{1,-1,3,-3\right\}\)
Ta có bảng sau:
| 2n-1 | 1 | -1 | 3 | -3 |
| n | 1 | 0 | 2 | -1 |
Vậy n={-1, 0, 1, 2}
Các bạn ơi!!!ủng hộ mik nha
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