a. \(4\dfrac{1}{4}-2\dfrac{5}{8}+2\dfrac{3}{5}=\dfrac{17}{4}-\dfrac{21}{8}+\dfrac{13}{5}=\dfrac{169}{40}\)
b. \(4\dfrac{4}{9}:2\dfrac{2}{3}+3\dfrac{1}{6}=\dfrac{40}{9}:\dfrac{8}{3}+\dfrac{19}{6}=\dfrac{5}{3}+\dfrac{19}{6}=\dfrac{29}{6}\)
c. \(3\dfrac{1}{5}+2\dfrac{3}{5}-2\dfrac{4}{5}=\dfrac{16}{5}+\dfrac{13}{5}-\dfrac{14}{5}=\dfrac{16+13-14}{5}=\dfrac{15}{5}=3\)
d. \(5\dfrac{1}{7}-2\dfrac{4}{5}:1\dfrac{1}{5}=\dfrac{36}{7}-\dfrac{14}{5}:\dfrac{6}{5}=\dfrac{36}{7}-\dfrac{7}{3}=\dfrac{59}{21}\)
e. \(2\dfrac{3}{5}+1\dfrac{1}{4}.2\dfrac{2}{3}=\dfrac{13}{5}+\dfrac{5}{4}.\dfrac{8}{3}=\dfrac{13}{5}+\dfrac{10}{3}=\dfrac{89}{15}\)
g. \(4\dfrac{1}{3}.1\dfrac{1}{2}+5\dfrac{2}{7}=\dfrac{13}{3}.\dfrac{3}{2}+\dfrac{37}{7}=\dfrac{13}{2}+\dfrac{37}{7}=\dfrac{165}{14}\)
