Question

Mọi người e vs ạ

a) \(\left(x+\frac{1}{3}\right)^3=\frac{-8}{27}\)

b)\(\frac{1}{4}x-\frac{8}{12}=1-\frac{3}{2}x\)

Answer 1

\(a,\left[x+\frac{1}{3}\right]^3=-\frac{8}{27}\)

\(\Leftrightarrow\left[x+\frac{1}{3}\right]^3=\left[-\frac{2}{3}\right]^3\)

\(\Leftrightarrow x+\frac{1}{3}=-\frac{2}{3}\)

\(\Leftrightarrow x=-\frac{2}{3}-\frac{1}{3}=-1\)

Vậy x = -1

Answer 2

a) (x+1/3)³ = -8/27

<=> (x+1/3)³ = (-2/3)³

<=> x + 1/3 = -2/3

<=> x = -1

b) \(\frac{1}{4}x-\frac{8}{12}=1-\frac{3}{2}x\)

\(\Leftrightarrow\frac{7}{4}x=\frac{5}{3}\)

<=> x = 20/21

Answer 3

a,\(\left(x+\frac{1}{3}\right)^3=\frac{-8}{27}\)

\(\Leftrightarrow\left(x+\frac{1}{3}\right)^3=\left(-\frac{2}{3}\right)^3\)

\(\Leftrightarrow x+\frac{1}{3}=-\frac{2}{3}\)

\(\Leftrightarrow x=-\frac{2}{3}-\frac{1}{3}=-1\)

Vậy x = -1 

b, \(\frac{1}{4}x-\frac{8}{12}=1-\frac{3}{2}x\)

\(\Leftrightarrow\frac{3x-8}{12}=\frac{2-3x}{2}\)

\(\Leftrightarrow\left(3x-8\right)2=12\left(2-3x\right)\)

\(\Leftrightarrow6x-16=24-36x\)

\(\Leftrightarrow42x=40\)

\(\Leftrightarrow x=\frac{40}{42}=\frac{20}{21}\)

Vậy \(x=\frac{20}{21}\)

Answer 4

\(b,\frac{1}{4}x-\frac{8}{12}=1-\frac{3}{2}x\)

\(\Leftrightarrow\frac{3}{12}x-\frac{8}{12}=\frac{2-3}{2}x\)

\(\Leftrightarrow\frac{3x-8}{12}x=\frac{2-3}{2}x\)

Nhân chéo vào rồi sau đó tìm kết quả của x thôi

Answer 5

Lộn tí , bỏ chữ x vào \(\frac{3x-8}{12}x\)đi rồi để \(\frac{2-3x}{2}\)nhé

Do mình lỡ đăng gửi trả lời luôn nên ghi lộn

Answer 6

\(a,\left(x+\frac{1}{3}\right)^3=-\frac{8}{27}\)

\(\Rightarrow\left(x+\frac{1}{3}\right)^3=\left(-\frac{2}{3}\right)^3\)

\(\Rightarrow x+\frac{1}{3}=-\frac{2}{3}\)

\(\Rightarrow x=-\frac{2}{3}-\frac{1}{3}\)

\(\Rightarrow x=-1\)

Answer 7

\(b,\frac{1}{4}x-\frac{8}{12}=1-\frac{3}{2}x\)

\(\frac{3x-8}{12}=\frac{2-3x}{2}\)

\(6x-16=24-36x\)

\(42x=40\)

\(x=\frac{20}{21}\)