\(\text{a) 7-2x=22-9x}\)
\(\Leftrightarrow\text{7-2x-22+9x=0}\)
\(\Leftrightarrow-15+7x=0\)
\(\Leftrightarrow7x=15\)
\(\Leftrightarrow x=\frac{15}{7}\)
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#Thảo Vy#
\(\text{b) x-12+4x=25+2x-1}\)
\(\Leftrightarrow x-12+4x-25-2x+1=0\)
\(\Leftrightarrow3x-36=0\)
\(\Leftrightarrow x=\frac{36}{3}=12\)
Vậy..
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#Thảo Vy#