Question

Mn giúp tui vs tui cần gấp

Answer 1

c) \(ĐKXĐ:x\ne0;x\ne2\).

\(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x^2-2x}\)

\(\Leftrightarrow\dfrac{x\left(x+2\right)}{x\left(x-2\right)}-\dfrac{x-2}{x\left(x-2\right)}=\dfrac{2}{x\left(x-2\right)}\)

\(\Rightarrow x^2+2x-x+2=2\)

\(\Leftrightarrow x^2+x=0\)

\(\Leftrightarrow x\left(x+1\right)=0\)

\(\Leftrightarrow x=0\left(loại\right)hayx=-1\left(nhận\right)\)

\(VậyS=\left\{-1\right\}\)