a. \(I=I1=I23=U:R=6:\left(1,8+\dfrac{3\cdot2}{3+2}\right)=2A\left(R1ntR23\right)\)
\(\rightarrow U1=I1\cdot R1=2\cdot1,8=3,6V\)
\(\rightarrow U23=U2=U3=I23\cdot R23=2\cdot\left(\dfrac{3\cdot2}{3+2}\right)=2,4V\left(R1//R2\right)\)
\(\Rightarrow\left\{{}\begin{matrix}I2=U2:R2=2,4:3=0,8A\\I3=U3:R3=2,4:2=1,2A\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}Q_{toa1}=A_1=U_1\cdot I_1\cdot t=3,6\cdot2\cdot1\cdot60=432\left(J\right)\\Q_{toa2}=A_2=U_2\cdot I_2\cdot t=2,4\cdot0,8\cdot1\cdot60=115,2\left(J\right)\end{matrix}\right.\)