Question

Mn giúp em với ạ🥺🥺

Answer 1

a) \(2\left(x+3\right)=4x-\left(2+x\right)\)

\(2x+6=3x-2\)

\(-x=-8\)=>x=8

Answer 2

b) \(\dfrac{1}{x+2}+\dfrac{5}{2-x}=\dfrac{2x-3}{x^2-4}\) đk x khác 2 và -2

\(\dfrac{\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}-\dfrac{5\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x-3}{\left(x-2\right)\left(x+2\right)}\)

=>\(x-2-5x-10=2x-3\)

\(-6x=9=>x=\dfrac{3}{2}tm\)

Answer 3

c) I x-9 I =2x -5

TH1 : x-9 =2x-5 (x≥9)

-x=4=>x=-4 ktm

TH2 9-x=2x-5 (x≤9)

-3x=-14

x=\(\dfrac{14}{3}\) TM

 

Answer 4

d) \(\dfrac{1-2x}{2}\)≤ 1 \(+\dfrac{x+2}{3}\)

=>\(3\left(1-2x\right)\) ≤ 6 +\(2\left(x+2\right)\)

\(3-6x\) ≤ 6 + \(2x+4\)

\(-8x\)≤7

\(x\text{≤}\dfrac{-7}{8}\)