Bài 15:
a. \(\left\{{}\begin{matrix}v_1=\dfrac{s_1}{t_1}=\dfrac{60}{1+\dfrac{15}{60}}=48\left(\dfrac{km}{h}\right)\\v_2=\dfrac{s_2}{t_2}=\dfrac{40}{\left(10-8\right)-\left(1+\dfrac{15}{60}\right)}=\dfrac{160}{3}\left(\dfrac{km}{h}\right)\end{matrix}\right.\)
b. \(v_{tb}=\dfrac{s_1+s_2}{t_1+t_2}=\dfrac{60+40}{10-8}=50\left(\dfrac{km}{h}\right)\)