a)
\(3^{3x+1}=\frac{10935}{5}\)
\(3^{3x+1}=2187=3^7\)
\(\Rightarrow3x+1=7\)
\(3x=7-1\)
\(3x=6\)
\(x=\frac{6}{3}=2\)
a)3^3x+1=10935/5
=>3^3x+1=2187
=>3^3x+1=3^7
=>3x+1=7
=>3x=6
=>x=2
Vậy x=2
a, 33x+1.5=10935
33x+1=10935:5
33x+1=2187
33x+1=37
3x+1=7
3x=7-1
3x=6
x=6:3
x=2
vạy ...
b,25x+1.3=6144
25x+1=6144:3
25x+1=2048
25x+1=211
5x+1=11
5x=11-1
5x=10
x=10:5
x=2
vậy...
b)
\(2^{5x+1}=\frac{6144}{3}=2048=2^{11}\)
\(\Rightarrow5x+1=11\)
\(5x=11-1=10\)
\(x=\frac{10}{5}=2\)
phần b tương tự nha bạn
